"open file -a AppleScriptApp" question

I exported my script as application. And I want to use it as follows:

$ open ~/some_file -a my_applescript_application

Inside of script I handle args:

on run argv
    if (count of argv) > 0 then
        -- do something with item 1 of argv
        -- I expect it to be the path of file I am trying to open
        return "defined"
    else
        return "failed"
    end if
end run

Is it even possible?